Bellman-Ford algorithm in C++

I implemented modified Bellman-Ford recently in Python for a client, so it's still fairly fresh in my mind. Working from a template is no problem at all. I assume the existing code is robust and correct, and would contact you before making any adjustments to it -- but obviously would prefer to leave it as-is. (Speaking of the template, I can't seem to find where you've uploaded it in your proposal. I'm sure it's easy enough to follow, however, and I'm confident this bid is accurate.) I have an Ubuntu 16.04 machine, so there likely won't be any platform issues. My process typically involves following the Unix philosophy and TDD to produce robust and modular code, so I'm confident you'll be happy with what I can turn around in one day. Thanks for your time and consideration.

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Hi I have done several graph related projects using C++. I think i can this in a day. I don't see your template. Can you please share? Some of my C/C++ projects and got good reviews: https://www.freelancer.com/projects/software-architecture/authentication-data-stream-via-bytearray/ https://www.freelancer.com/projects/c-programming/project-graph-theory-find-the/ https://www.freelancer.com/projects/cplusplus-programming/write-program-for/ https://www.freelancer.com/projects/software-architecture/personalproject/ I write original code from scratch and is never copied from the internet. I assure you of clean and well commented code. I would love to take up this project and definitely finish up in quick time with your satisfaction. Looking forward to working on this one. Please send me a message Background: Software developer by profession having 7+ years of experience in C, C++, Python and other scripting languages for automation. I have worked on RESTful APIs as well.

Hello, I have a major in computer science. I have done various projects in c++. I am well versed in algorithms and knows the Bellman Ford algorithm. I will also optimise the algorithm to the possible extent considering scalability. I will complete the whole project in the given deadline. I use Ubuntu for coding.

#include <iostream> #include <stdlib.h> #include <string.h> #include <limits.h> using namespace std; struct Edge { // This structure is equal to an edge. Edge contains two end points. These edges are directed //edges so they contain source and destination and some weight. These 3 are elements in this //structure int source, destination, weight; }; // a structure to represent a connected, directed and weighted graph struct Graph { int V, E; // V is number of vertices and E is number of edges struct Edge* edge; // This structure contain another structure which we already created edge. }; struct Graph* createGraph(int V, int E) { struct Graph* graph = (struct Graph*) malloc( sizeof(struct Graph)); //Allocating space to structure graph graph->V = V; //assigning values to structure elements that taken form user. graph->E = E; graph->edge = (struct Edge*) malloc( graph->E * sizeof( struct Edge ) ); //Creating "Edge" type structures inside "Graph" structure, the number of edge type structures are equal to number of edges return graph; } void FinalSolution(int dist[], int n) { // This function prints the final solution cout<<"\nVertex\tDistance from Source Vertex\n"; int i; for (i = 0; i < n; ++i){ cout<<i<<"\t\t"<<dist[i]<<"\n"; } } void BellmanFord(struct Graph* graph, int source) { int V = graph->V; int E = graph->E; int StoreDistance[V]; int i,j; // initial step : rest : chat

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Hi My approach for this problem is as follows: Initialize distances from source to all vertices as infinite and distance to source itself as 0. Create an array dist[] of size |V| with all values as infinite except dist[src] where src is source vertex. 2) This step calculates shortest distances. Do following |V|-1 times where |V| is the number of vertices in given graph. …..a) Do following for each edge u-v ………………If dist[v] > dist[u] + weight of edge uv, then update dist[v] ………………….dist[v] = dist[u] + weight of edge uv 3) This step reports if there is a negative weight cycle in graph. Do following for each edge u-v ……If dist[v] > dist[u] + weight of edge uv, then “Graph contains negative weight cycle” The idea of step 3 is, step 2 guarantees shortest distances if graph doesn’t contain negative weight cycle. If we iterate through all edges one more time and get a shorter path for any vertex, then there is a negative weight cycle. I hope you undrstand my approach and consider me in giving this project to me. Regards Pankaj